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Soda ash comes in powder form that must be mixed into a liquid solution and added into the water supply. Add a teaspoon of baking soda to the water and mix well with a whisk or spoon until the baking soda dissolves completely. The hyperbolic space is a conformally compact Einstein manifold, Generic Doubly-Linked-Lists C implementation. Because NaOH is a strong base and is soluble, the [ OH ] will be equal to the concentration of the NaOH. I'll check the alkalinity too, as you suggest. Varmebaronen UB 40 with 660 gallons of pressurized storage - first fire 10/08/2012. What was the actual cockpit layout and crew of the Mi-24A? I have a body of water (volume=x) with about pH: 5.5 and alkalinity of about 4,5 mg/L CaCO3. Untreated water flows through the filter, which is filled with calcium carbonate (limestone) or a synthetic magnesium oxide medium. You can't measure the pH of baking soda because it is a dry powder. On the other hand, low pH acidic water can corrode plumbing and leach metals. How to calculate the pH of a sodium bicarbonate-sodium hydroxide buffer solution? The biggest drawback to neutralizing filters is that they may increase or cause water hardness if calcium and magnesium are used in the filter. Asking for help, clarification, or responding to other answers. You dont want to fix one problem just to create another. How do I calculate how much sodium hydroxide I need to add to get a new pH? A blanket statement related to scaling potential is misleading when applied to typical hot water boilers that are low pressure and for practical purposes are sealed, that is, fresh water is not supplied on a regular basis or the boiler water is not regularly drained and refilled. I have to treat roughly 1060 gallons contained in the storage, piping, and Solo Innova . One exception would be if the water was over saturated with carbon dioxide (sparkling water) the pH would probably not change with NaOH addition until enough of the gas was converted to bicarbonate so that no more gas would leave the solution on its own. $$\mathrm{V}_\ce{(NaOH)_\text{added}}=\pu{1.679\times{10^{-6}}~L}$$.